y^2+12y+27=(y+9)(y+)

Solution for y^2+12y+27=(y+9)(y+) equation:

y^2+12y+27=(y+9)(y+)

We move all terms to the left:

y^2+12y+27-((y+9)(y+))=0

We add all the numbers together, and all the variables

y^2+12y-((y+9)(+y))+27=0

We multiply parentheses ..

y^2-((+y^2+9y))+12y+27=0


We calculate terms in parentheses: -((+y^2+9y)), so:

(+y^2+9y)

We get rid of parentheses

y^2+9y

Back to the equation:

-(y^2+9y)


We add all the numbers together, and all the variables

y^2+12y-(y^2+9y)+27=0

We get rid of parentheses

y^2-y^2+12y-9y+27=0

We add all the numbers together, and all the variables

3y+27=0

We move all terms containing y to the left, all other terms to the right

3y=-27

y=-27/3

y=-9